@node Obstacks,Licenses,Functions,Top@chapter Obstacks@cindex obstacksAn @dfn{obstack} is a pool of memory containing a stack of objects. Youcan create any number of separate obstacks, and then allocate objects inspecified obstacks. Within each obstack, the last object allocated mustalways be the first one freed, but distinct obstacks are independent ofeach other.Aside from this one constraint of order of freeing, obstacks are totallygeneral: an obstack can contain any number of objects of any size. Theyare implemented with macros, so allocation is usually very fast as long asthe objects are usually small. And the only space overhead per object isthe padding needed to start each object on a suitable boundary.@menu* Creating Obstacks:: How to declare an obstack in your program.* Preparing for Obstacks:: Preparations needed before you canuse obstacks.* Allocation in an Obstack:: Allocating objects in an obstack.* Freeing Obstack Objects:: Freeing objects in an obstack.* Obstack Functions:: The obstack functions are bothfunctions and macros.* Growing Objects:: Making an object bigger by stages.* Extra Fast Growing:: Extra-high-efficiency (though morecomplicated) growing objects.* Status of an Obstack:: Inquiries about the status of an obstack.* Obstacks Data Alignment:: Controlling alignment of objects in obstacks.* Obstack Chunks:: How obstacks obtain and release chunks;efficiency considerations.* Summary of Obstacks::@end menu@node Creating Obstacks@section Creating ObstacksThe utilities for manipulating obstacks are declared in the headerfile @file{obstack.h}.@pindex obstack.h@comment obstack.h@comment GNU@deftp {Data Type} {struct obstack}An obstack is represented by a data structure of type @code{structobstack}. This structure has a small fixed size; it records the statusof the obstack and how to find the space in which objects are allocated.It does not contain any of the objects themselves. You should not tryto access the contents of the structure directly; use only the functionsdescribed in this chapter.@end deftpYou can declare variables of type @code{struct obstack} and use them asobstacks, or you can allocate obstacks dynamically like any other kindof object. Dynamic allocation of obstacks allows your program to have avariable number of different stacks. (You can even allocate anobstack structure in another obstack, but this is rarely useful.)All the functions that work with obstacks require you to specify whichobstack to use. You do this with a pointer of type @code{struct obstack*}. In the following, we often say ``an obstack'' when strictlyspeaking the object at hand is such a pointer.The objects in the obstack are packed into large blocks called@dfn{chunks}. The @code{struct obstack} structure points to a chain ofthe chunks currently in use.The obstack library obtains a new chunk whenever you allocate an objectthat won't fit in the previous chunk. Since the obstack library manageschunks automatically, you don't need to pay much attention to them, butyou do need to supply a function which the obstack library should use toget a chunk. Usually you supply a function which uses @code{malloc}directly or indirectly. You must also supply a function to free a chunk.These matters are described in the following section.@node Preparing for Obstacks@section Preparing for Using ObstacksEach source file in which you plan to use the obstack functionsmust include the header file @file{obstack.h}, like this:@smallexample#include <obstack.h>@end smallexample@findex obstack_chunk_alloc@findex obstack_chunk_freeAlso, if the source file uses the macro @code{obstack_init}, it mustdeclare or define two functions or macros that will be called by theobstack library. One, @code{obstack_chunk_alloc}, is used to allocatethe chunks of memory into which objects are packed. The other,@code{obstack_chunk_free}, is used to return chunks when the objects inthem are freed. These macros should appear before any use of obstacksin the source file.Usually these are defined to use @code{malloc} via the intermediary@code{xmalloc} (@pxref{Unconstrained Allocation, , , libc, The GNU C Library Reference Manual}). This is done withthe following pair of macro definitions:@smallexample#define obstack_chunk_alloc xmalloc#define obstack_chunk_free free@end smallexample@noindentThough the memory you get using obstacks really comes from @code{malloc},using obstacks is faster because @code{malloc} is called less often, forlarger blocks of memory. @xref{Obstack Chunks}, for full details.At run time, before the program can use a @code{struct obstack} objectas an obstack, it must initialize the obstack by calling@code{obstack_init}.@comment obstack.h@comment GNU@deftypefun int obstack_init (struct obstack *@var{obstack-ptr})Initialize obstack @var{obstack-ptr} for allocation of objects. Thisfunction calls the obstack's @code{obstack_chunk_alloc} function. Ifallocation of memory fails, the function pointed to by@code{obstack_alloc_failed_handler} is called. The @code{obstack_init}function always returns 1 (Compatibility notice: Former versions ofobstack returned 0 if allocation failed).@end deftypefunHere are two examples of how to allocate the space for an obstack andinitialize it. First, an obstack that is a static variable:@smallexamplestatic struct obstack myobstack;@dots{}obstack_init (&myobstack);@end smallexample@noindentSecond, an obstack that is itself dynamically allocated:@smallexamplestruct obstack *myobstack_ptr= (struct obstack *) xmalloc (sizeof (struct obstack));obstack_init (myobstack_ptr);@end smallexample@comment obstack.h@comment GNU@defvar obstack_alloc_failed_handlerThe value of this variable is a pointer to a function that@code{obstack} uses when @code{obstack_chunk_alloc} fails to allocatememory. The default action is to print a message and abort.You should supply a function that either calls @code{exit}(@pxref{Program Termination, , , libc, The GNU C Library Reference Manual}) or @code{longjmp} (@pxref{Non-LocalExits, , , libc, The GNU C Library Reference Manual}) and doesn't return.@smallexamplevoid my_obstack_alloc_failed (void)@dots{}obstack_alloc_failed_handler = &my_obstack_alloc_failed;@end smallexample@end defvar@node Allocation in an Obstack@section Allocation in an Obstack@cindex allocation (obstacks)The most direct way to allocate an object in an obstack is with@code{obstack_alloc}, which is invoked almost like @code{malloc}.@comment obstack.h@comment GNU@deftypefun {void *} obstack_alloc (struct obstack *@var{obstack-ptr}, int @var{size})This allocates an uninitialized block of @var{size} bytes in an obstackand returns its address. Here @var{obstack-ptr} specifies which obstackto allocate the block in; it is the address of the @code{struct obstack}object which represents the obstack. Each obstack function or macrorequires you to specify an @var{obstack-ptr} as the first argument.This function calls the obstack's @code{obstack_chunk_alloc} function ifit needs to allocate a new chunk of memory; it calls@code{obstack_alloc_failed_handler} if allocation of memory by@code{obstack_chunk_alloc} failed.@end deftypefunFor example, here is a function that allocates a copy of a string @var{str}in a specific obstack, which is in the variable @code{string_obstack}:@smallexamplestruct obstack string_obstack;char *copystring (char *string)@{size_t len = strlen (string) + 1;char *s = (char *) obstack_alloc (&string_obstack, len);memcpy (s, string, len);return s;@}@end smallexampleTo allocate a block with specified contents, use the function@code{obstack_copy}, declared like this:@comment obstack.h@comment GNU@deftypefun {void *} obstack_copy (struct obstack *@var{obstack-ptr}, void *@var{address}, int @var{size})This allocates a block and initializes it by copying @var{size}bytes of data starting at @var{address}. It calls@code{obstack_alloc_failed_handler} if allocation of memory by@code{obstack_chunk_alloc} failed.@end deftypefun@comment obstack.h@comment GNU@deftypefun {void *} obstack_copy0 (struct obstack *@var{obstack-ptr}, void *@var{address}, int @var{size})Like @code{obstack_copy}, but appends an extra byte containing a nullcharacter. This extra byte is not counted in the argument @var{size}.@end deftypefunThe @code{obstack_copy0} function is convenient for copying a sequenceof characters into an obstack as a null-terminated string. Here is anexample of its use:@smallexamplechar *obstack_savestring (char *addr, int size)@{return obstack_copy0 (&myobstack, addr, size);@}@end smallexample@noindentContrast this with the previous example of @code{savestring} using@code{malloc} (@pxref{Basic Allocation, , , libc, The GNU C Library Reference Manual}).@node Freeing Obstack Objects@section Freeing Objects in an Obstack@cindex freeing (obstacks)To free an object allocated in an obstack, use the function@code{obstack_free}. Since the obstack is a stack of objects, freeingone object automatically frees all other objects allocated more recentlyin the same obstack.@comment obstack.h@comment GNU@deftypefun void obstack_free (struct obstack *@var{obstack-ptr}, void *@var{object})If @var{object} is a null pointer, everything allocated in the obstackis freed. Otherwise, @var{object} must be the address of an objectallocated in the obstack. Then @var{object} is freed, along witheverything allocated in @var{obstack} since @var{object}.@end deftypefunNote that if @var{object} is a null pointer, the result is anuninitialized obstack. To free all memory in an obstack but leave itvalid for further allocation, call @code{obstack_free} with the addressof the first object allocated on the obstack:@smallexampleobstack_free (obstack_ptr, first_object_allocated_ptr);@end smallexampleRecall that the objects in an obstack are grouped into chunks. When allthe objects in a chunk become free, the obstack library automaticallyfrees the chunk (@pxref{Preparing for Obstacks}). Then otherobstacks, or non-obstack allocation, can reuse the space of the chunk.@node Obstack Functions@section Obstack Functions and Macros@cindex macrosThe interfaces for using obstacks may be defined either as functions oras macros, depending on the compiler. The obstack facility works withall C compilers, including both @w{ISO C} and traditional C, but there areprecautions you must take if you plan to use compilers other than GNU C.If you are using an old-fashioned @w{non-ISO C} compiler, all the obstack``functions'' are actually defined only as macros. You can call thesemacros like functions, but you cannot use them in any other way (forexample, you cannot take their address).Calling the macros requires a special precaution: namely, the firstoperand (the obstack pointer) may not contain any side effects, becauseit may be computed more than once. For example, if you write this:@smallexampleobstack_alloc (get_obstack (), 4);@end smallexample@noindentyou will find that @code{get_obstack} may be called several times.If you use @code{*obstack_list_ptr++} as the obstack pointer argument,you will get very strange results since the incrementation may occurseveral times.In @w{ISO C}, each function has both a macro definition and a functiondefinition. The function definition is used if you take the address of thefunction without calling it. An ordinary call uses the macro definition bydefault, but you can request the function definition instead by writing thefunction name in parentheses, as shown here:@smallexamplechar *x;void *(*funcp) ();/* @r{Use the macro}. */x = (char *) obstack_alloc (obptr, size);/* @r{Call the function}. */x = (char *) (obstack_alloc) (obptr, size);/* @r{Take the address of the function}. */funcp = obstack_alloc;@end smallexample@noindentThis is the same situation that exists in @w{ISO C} for the standard libraryfunctions. @xref{Macro Definitions, , , libc, The GNU C Library Reference Manual}.@strong{Warning:} When you do use the macros, you must observe theprecaution of avoiding side effects in the first operand, even in @w{ISO C}.If you use the GNU C compiler, this precaution is not necessary, becausevarious language extensions in GNU C permit defining the macros so as tocompute each argument only once.@node Growing Objects@section Growing Objects@cindex growing objects (in obstacks)@cindex changing the size of a block (obstacks)Because memory in obstack chunks is used sequentially, it is possible tobuild up an object step by step, adding one or more bytes at a time to theend of the object. With this technique, you do not need to know how muchdata you will put in the object until you come to the end of it. We callthis the technique of @dfn{growing objects}. The special functionsfor adding data to the growing object are described in this section.You don't need to do anything special when you start to grow an object.Using one of the functions to add data to the object automaticallystarts it. However, it is necessary to say explicitly when the object isfinished. This is done with the function @code{obstack_finish}.The actual address of the object thus built up is not known until theobject is finished. Until then, it always remains possible that you willadd so much data that the object must be copied into a new chunk.While the obstack is in use for a growing object, you cannot use it forordinary allocation of another object. If you try to do so, the spacealready added to the growing object will become part of the other object.@comment obstack.h@comment GNU@deftypefun void obstack_blank (struct obstack *@var{obstack-ptr}, int @var{size})The most basic function for adding to a growing object is@code{obstack_blank}, which adds space without initializing it.@end deftypefun@comment obstack.h@comment GNU@deftypefun void obstack_grow (struct obstack *@var{obstack-ptr}, void *@var{data}, int @var{size})To add a block of initialized space, use @code{obstack_grow}, which isthe growing-object analogue of @code{obstack_copy}. It adds @var{size}bytes of data to the growing object, copying the contents from@var{data}.@end deftypefun@comment obstack.h@comment GNU@deftypefun void obstack_grow0 (struct obstack *@var{obstack-ptr}, void *@var{data}, int @var{size})This is the growing-object analogue of @code{obstack_copy0}. It adds@var{size} bytes copied from @var{data}, followed by an additional nullcharacter.@end deftypefun@comment obstack.h@comment GNU@deftypefun void obstack_1grow (struct obstack *@var{obstack-ptr}, char @var{c})To add one character at a time, use the function @code{obstack_1grow}.It adds a single byte containing @var{c} to the growing object.@end deftypefun@comment obstack.h@comment GNU@deftypefun void obstack_ptr_grow (struct obstack *@var{obstack-ptr}, void *@var{data})Adding the value of a pointer one can use the function@code{obstack_ptr_grow}. It adds @code{sizeof (void *)} bytescontaining the value of @var{data}.@end deftypefun@comment obstack.h@comment GNU@deftypefun void obstack_int_grow (struct obstack *@var{obstack-ptr}, int @var{data})A single value of type @code{int} can be added by using the@code{obstack_int_grow} function. It adds @code{sizeof (int)} bytes tothe growing object and initializes them with the value of @var{data}.@end deftypefun@comment obstack.h@comment GNU@deftypefun {void *} obstack_finish (struct obstack *@var{obstack-ptr})When you are finished growing the object, use the function@code{obstack_finish} to close it off and return its final address.Once you have finished the object, the obstack is available for ordinaryallocation or for growing another object.This function can return a null pointer under the same conditions as@code{obstack_alloc} (@pxref{Allocation in an Obstack}).@end deftypefunWhen you build an object by growing it, you will probably need to knowafterward how long it became. You need not keep track of this as you growthe object, because you can find out the length from the obstack justbefore finishing the object with the function @code{obstack_object_size},declared as follows:@comment obstack.h@comment GNU@deftypefun int obstack_object_size (struct obstack *@var{obstack-ptr})This function returns the current size of the growing object, in bytes.Remember to call this function @emph{before} finishing the object.After it is finished, @code{obstack_object_size} will return zero.@end deftypefunIf you have started growing an object and wish to cancel it, you shouldfinish it and then free it, like this:@smallexampleobstack_free (obstack_ptr, obstack_finish (obstack_ptr));@end smallexample@noindentThis has no effect if no object was growing.@cindex shrinking objectsYou can use @code{obstack_blank} with a negative size argument to makethe current object smaller. Just don't try to shrink it beyond zerolength---there's no telling what will happen if you do that.@node Extra Fast Growing@section Extra Fast Growing Objects@cindex efficiency and obstacksThe usual functions for growing objects incur overhead for checkingwhether there is room for the new growth in the current chunk. If youare frequently constructing objects in small steps of growth, thisoverhead can be significant.You can reduce the overhead by using special ``fast growth''functions that grow the object without checking. In order to have arobust program, you must do the checking yourself. If you do this checkingin the simplest way each time you are about to add data to the object, youhave not saved anything, because that is what the ordinary growthfunctions do. But if you can arrange to check less often, or checkmore efficiently, then you make the program faster.The function @code{obstack_room} returns the amount of room availablein the current chunk. It is declared as follows:@comment obstack.h@comment GNU@deftypefun int obstack_room (struct obstack *@var{obstack-ptr})This returns the number of bytes that can be added safely to the currentgrowing object (or to an object about to be started) in obstack@var{obstack} using the fast growth functions.@end deftypefunWhile you know there is room, you can use these fast growth functionsfor adding data to a growing object:@comment obstack.h@comment GNU@deftypefun void obstack_1grow_fast (struct obstack *@var{obstack-ptr}, char @var{c})The function @code{obstack_1grow_fast} adds one byte containing thecharacter @var{c} to the growing object in obstack @var{obstack-ptr}.@end deftypefun@comment obstack.h@comment GNU@deftypefun void obstack_ptr_grow_fast (struct obstack *@var{obstack-ptr}, void *@var{data})The function @code{obstack_ptr_grow_fast} adds @code{sizeof (void *)}bytes containing the value of @var{data} to the growing object inobstack @var{obstack-ptr}.@end deftypefun@comment obstack.h@comment GNU@deftypefun void obstack_int_grow_fast (struct obstack *@var{obstack-ptr}, int @var{data})The function @code{obstack_int_grow_fast} adds @code{sizeof (int)} bytescontaining the value of @var{data} to the growing object in obstack@var{obstack-ptr}.@end deftypefun@comment obstack.h@comment GNU@deftypefun void obstack_blank_fast (struct obstack *@var{obstack-ptr}, int @var{size})The function @code{obstack_blank_fast} adds @var{size} bytes to thegrowing object in obstack @var{obstack-ptr} without initializing them.@end deftypefunWhen you check for space using @code{obstack_room} and there is notenough room for what you want to add, the fast growth functionsare not safe. In this case, simply use the corresponding ordinarygrowth function instead. Very soon this will copy the object to anew chunk; then there will be lots of room available again.So, each time you use an ordinary growth function, check afterward forsufficient space using @code{obstack_room}. Once the object is copiedto a new chunk, there will be plenty of space again, so the program willstart using the fast growth functions again.Here is an example:@smallexample@groupvoidadd_string (struct obstack *obstack, const char *ptr, int len)@{while (len > 0)@{int room = obstack_room (obstack);if (room == 0)@{/* @r{Not enough room. Add one character slowly,}@r{which may copy to a new chunk and make room.} */obstack_1grow (obstack, *ptr++);len--;@}else@{if (room > len)room = len;/* @r{Add fast as much as we have room for.} */len -= room;while (room-- > 0)obstack_1grow_fast (obstack, *ptr++);@}@}@}@end group@end smallexample@node Status of an Obstack@section Status of an Obstack@cindex obstack status@cindex status of obstackHere are functions that provide information on the current status ofallocation in an obstack. You can use them to learn about an object whilestill growing it.@comment obstack.h@comment GNU@deftypefun {void *} obstack_base (struct obstack *@var{obstack-ptr})This function returns the tentative address of the beginning of thecurrently growing object in @var{obstack-ptr}. If you finish the objectimmediately, it will have that address. If you make it larger first, itmay outgrow the current chunk---then its address will change!If no object is growing, this value says where the next object youallocate will start (once again assuming it fits in the currentchunk).@end deftypefun@comment obstack.h@comment GNU@deftypefun {void *} obstack_next_free (struct obstack *@var{obstack-ptr})This function returns the address of the first free byte in the currentchunk of obstack @var{obstack-ptr}. This is the end of the currentlygrowing object. If no object is growing, @code{obstack_next_free}returns the same value as @code{obstack_base}.@end deftypefun@comment obstack.h@comment GNU@deftypefun int obstack_object_size (struct obstack *@var{obstack-ptr})This function returns the size in bytes of the currently growing object.This is equivalent to@smallexampleobstack_next_free (@var{obstack-ptr}) - obstack_base (@var{obstack-ptr})@end smallexample@end deftypefun@node Obstacks Data Alignment@section Alignment of Data in Obstacks@cindex alignment (in obstacks)Each obstack has an @dfn{alignment boundary}; each object allocated inthe obstack automatically starts on an address that is a multiple of thespecified boundary. By default, this boundary is 4 bytes.To access an obstack's alignment boundary, use the macro@code{obstack_alignment_mask}, whose function prototype looks likethis:@comment obstack.h@comment GNU@deftypefn Macro int obstack_alignment_mask (struct obstack *@var{obstack-ptr})The value is a bit mask; a bit that is 1 indicates that the correspondingbit in the address of an object should be 0. The mask value should be oneless than a power of 2; the effect is that all object addresses aremultiples of that power of 2. The default value of the mask is 3, so thataddresses are multiples of 4. A mask value of 0 means an object can starton any multiple of 1 (that is, no alignment is required).The expansion of the macro @code{obstack_alignment_mask} is an lvalue,so you can alter the mask by assignment. For example, this statement:@smallexampleobstack_alignment_mask (obstack_ptr) = 0;@end smallexample@noindenthas the effect of turning off alignment processing in the specified obstack.@end deftypefnNote that a change in alignment mask does not take effect until@emph{after} the next time an object is allocated or finished in theobstack. If you are not growing an object, you can make the newalignment mask take effect immediately by calling @code{obstack_finish}.This will finish a zero-length object and then do proper alignment forthe next object.@node Obstack Chunks@section Obstack Chunks@cindex efficiency of chunks@cindex chunksObstacks work by allocating space for themselves in large chunks, andthen parceling out space in the chunks to satisfy your requests. Chunksare normally 4096 bytes long unless you specify a different chunk size.The chunk size includes 8 bytes of overhead that are not actually usedfor storing objects. Regardless of the specified size, longer chunkswill be allocated when necessary for long objects.The obstack library allocates chunks by calling the function@code{obstack_chunk_alloc}, which you must define. When a chunk is nolonger needed because you have freed all the objects in it, the obstacklibrary frees the chunk by calling @code{obstack_chunk_free}, which youmust also define.These two must be defined (as macros) or declared (as functions) in eachsource file that uses @code{obstack_init} (@pxref{Creating Obstacks}).Most often they are defined as macros like this:@smallexample#define obstack_chunk_alloc malloc#define obstack_chunk_free free@end smallexampleNote that these are simple macros (no arguments). Macro definitions witharguments will not work! It is necessary that @code{obstack_chunk_alloc}or @code{obstack_chunk_free}, alone, expand into a function name if it isnot itself a function name.If you allocate chunks with @code{malloc}, the chunk size should be apower of 2. The default chunk size, 4096, was chosen because it is longenough to satisfy many typical requests on the obstack yet short enoughnot to waste too much memory in the portion of the last chunk not yet used.@comment obstack.h@comment GNU@deftypefn Macro int obstack_chunk_size (struct obstack *@var{obstack-ptr})This returns the chunk size of the given obstack.@end deftypefnSince this macro expands to an lvalue, you can specify a new chunk size byassigning it a new value. Doing so does not affect the chunks alreadyallocated, but will change the size of chunks allocated for that particularobstack in the future. It is unlikely to be useful to make the chunk sizesmaller, but making it larger might improve efficiency if you areallocating many objects whose size is comparable to the chunk size. Hereis how to do so cleanly:@smallexampleif (obstack_chunk_size (obstack_ptr) < @var{new-chunk-size})obstack_chunk_size (obstack_ptr) = @var{new-chunk-size};@end smallexample@node Summary of Obstacks@section Summary of Obstack FunctionsHere is a summary of all the functions associated with obstacks. Eachtakes the address of an obstack (@code{struct obstack *}) as its firstargument.@table @code@item void obstack_init (struct obstack *@var{obstack-ptr})Initialize use of an obstack. @xref{Creating Obstacks}.@item void *obstack_alloc (struct obstack *@var{obstack-ptr}, int @var{size})Allocate an object of @var{size} uninitialized bytes.@xref{Allocation in an Obstack}.@item void *obstack_copy (struct obstack *@var{obstack-ptr}, void *@var{address}, int @var{size})Allocate an object of @var{size} bytes, with contents copied from@var{address}. @xref{Allocation in an Obstack}.@item void *obstack_copy0 (struct obstack *@var{obstack-ptr}, void *@var{address}, int @var{size})Allocate an object of @var{size}+1 bytes, with @var{size} of them copiedfrom @var{address}, followed by a null character at the end.@xref{Allocation in an Obstack}.@item void obstack_free (struct obstack *@var{obstack-ptr}, void *@var{object})Free @var{object} (and everything allocated in the specified obstackmore recently than @var{object}). @xref{Freeing Obstack Objects}.@item void obstack_blank (struct obstack *@var{obstack-ptr}, int @var{size})Add @var{size} uninitialized bytes to a growing object.@xref{Growing Objects}.@item void obstack_grow (struct obstack *@var{obstack-ptr}, void *@var{address}, int @var{size})Add @var{size} bytes, copied from @var{address}, to a growing object.@xref{Growing Objects}.@item void obstack_grow0 (struct obstack *@var{obstack-ptr}, void *@var{address}, int @var{size})Add @var{size} bytes, copied from @var{address}, to a growing object,and then add another byte containing a null character. @xref{GrowingObjects}.@item void obstack_1grow (struct obstack *@var{obstack-ptr}, char @var{data-char})Add one byte containing @var{data-char} to a growing object.@xref{Growing Objects}.@item void *obstack_finish (struct obstack *@var{obstack-ptr})Finalize the object that is growing and return its permanent address.@xref{Growing Objects}.@item int obstack_object_size (struct obstack *@var{obstack-ptr})Get the current size of the currently growing object. @xref{GrowingObjects}.@item void obstack_blank_fast (struct obstack *@var{obstack-ptr}, int @var{size})Add @var{size} uninitialized bytes to a growing object without checkingthat there is enough room. @xref{Extra Fast Growing}.@item void obstack_1grow_fast (struct obstack *@var{obstack-ptr}, char @var{data-char})Add one byte containing @var{data-char} to a growing object withoutchecking that there is enough room. @xref{Extra Fast Growing}.@item int obstack_room (struct obstack *@var{obstack-ptr})Get the amount of room now available for growing the current object.@xref{Extra Fast Growing}.@item int obstack_alignment_mask (struct obstack *@var{obstack-ptr})The mask used for aligning the beginning of an object. This is anlvalue. @xref{Obstacks Data Alignment}.@item int obstack_chunk_size (struct obstack *@var{obstack-ptr})The size for allocating chunks. This is an lvalue. @xref{Obstack Chunks}.@item void *obstack_base (struct obstack *@var{obstack-ptr})Tentative starting address of the currently growing object.@xref{Status of an Obstack}.@item void *obstack_next_free (struct obstack *@var{obstack-ptr})Address just after the end of the currently growing object.@xref{Status of an Obstack}.@end table